Question

4x²+5√2x-3
find zeroes

Answer 1

Answer: \\ \\ 4x {}^{2} + 5 \sqrt{2} x - 3 = 0 \\ \\ = > a = 4 \: \: b = 5 \sqrt{2} \: \:and \: c = - 3 \\ \\ \\ now \\ \\ D = b {}^{2} - 4ac = (5 \sqrt{2} ) {}^{2} - 4(4)( - 3) = 50 + 48 = 98 \\ \\ \\ \\ x = \frac{ - b - \sqrt{D} }{2a} \: \: or \: \: \frac{ - b + \sqrt{D} }{2a} = \frac{ - 5 \sqrt{2} - \sqrt{98} }{8} \: \: or \: \: \frac{ - 5 \sqrt{2} + \sqrt{98} }{8} [/tex]

Answer 2

Refer The attachment ⬆

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