Math, asked by MrSage, 6 hours ago

4x²-6/4x=-10

Find the value of x by factorization method

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Answers

Answered by DJMarshmellow
1

Answer:

4*10-6 (IF 4x=10)

40-6

34

Answered by GraceS
3

\sf\huge\bold{Answer:}

Given :

 \tt\  \frac{4 {x}^{2} - 6 }{4}  =  - 10 \\

To find :

Value of x using factorisation

Solution :

 \tt\  \implies \frac{4 {x}^{2} - 6 }{4}  =  - 10 \\

  • Multiplying 4 on both sides.

 \tt\  \implies \frac{4 {x}^{2} - 6 }{4} \times 4  =  - 10 \times 4 \\

 \tt\  \implies \frac{4 {x}^{2} - 6 }{ \cancel4} \times  \cancel4  =  -  40 \\

 \tt\  \implies 4 {x}^{2} - 6 =  - 40

  • Adding 40 on both sides

 \tt\  \implies 4 {x}^{2}  - 6 + 40 = - 40 + 40

 \tt\  \implies 4 {x}^{2}  + 34 = 0

  • Factorising Quadratic equation

 \tt\  \implies 2(2 {x}^{2}  + 17) = 0

  • Dividng 2 on both sides

\tt\  \implies (2 {x}^{2}  + 17) =  \frac{0}{2}  \\

\tt\  \implies 2 {x}^{2}  + 17 =  0

  • Subtracting 17 from both sides

\tt\  \implies 2 {x}^{2}  + 17 - 17 = 0 - 17

\tt\  \implies 2 {x}^{2}  =  - 17

  • Dividing 2 on both sides

\tt\  \implies  \frac{2}{2}  {x}^{2}  =  - \frac{17}{2}  \\

\tt\  \implies \cancel  \frac{2}{2}  {x}^{2}  =  - \frac{17}{2}  \\

\tt\  \implies    {x}^{2}  =  - \frac{17}{2}  \\

  • Square root both sides

\tt\  \implies   \sqrt{ {x}^{2}}   =    \sqrt{ - \frac{17}{2}}   \\

 \tt\  \implies x =  \sqrt{ - \frac{17}{2}}  \\

  • √-1 = i(where i is iota, it is used to represent complex numbers)

 \tt\  \implies x =   \sqrt{ - 1} \times  \sqrt{  \frac{17}{2}}  \\

 \tt\  \implies x =   i \times  \sqrt{  \frac{17}{2}}  \\

 \tt\  \implies x =     \sqrt{  \frac{17}{2}}i  \\

 \boxed{   \underline{\red{ \rm \: x =     \sqrt{  \frac{17}{2}}i }}  }

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