Question

4x2 + 7x – 11 by 2x – 4
$\sqrt{05}$
(a+b)​

Answer 1

Answer:

Let p(x)= 8+7x-11 and g(x) = 2x-4

g(x)= 0=>2x-4=0

x=4/2= 2

Putting the value of 'x' in p(x)

8+7×2-11

8+14-11

11.

11 is remainder

Hope its helps