4x² - 8x + 3 = 0
2y2-7y+6=0
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4 x squared minus 8 x + 3 is equal to zero in Dubai
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Solution :-
Q: 4x² - 8x + 3 = 0
= 4x² - 2x - 6x + 3 = 0
=> 2x(2x - 1) - 3(2x - 1) = 0
=> (2x - 3) (2x - 1) = 0
=> x = 3/2 or x = 1/2
Q: 2y² - 7y + 6 = 0
=> 2y² - 4y - 3y + 6 = 0
=> 2y(y - 2) - 3(y - 2) = 0
=> (2y - 3) (y - 2) = 0
=> y = 3/2 or y = 2
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