Question

4x²-8x-4
find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the cofficient

Answer 1

Answer:

0 and -2

Step-by-step explanation:

4x² + 8x

= 4x ( x + 2)

To find Zeroes

4x ( x + 2) = 0

=> x = 0 & x = -2

Sum of Zeroes = 0 + (-2) = -2

Product of zeroes = 0 * (-2) = 0

Comparing 4x² + 8x

with ax² + bx + c

a = 4 , b = 8 , c = 0

Sum of Zeroes = -b/1 = - 8/4 = -2

Product of Zeroes = c/a = 0/4 = 0

Sum & product of zeroes relationship is verified as results matches.