Question

4x2 + 8x - 5
Factorise

Answer 1

Answer:

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Step-by-step explanation:

4x^2+8x-5

4x^2-2x+10x-5

2x(2x-1)5(2x-1)

2x-1=0 or 2x+5=0

x=1/2 or x= -5/2

Answer 2

Answer:

4x²+8x-5.

Lets split the middle term.

Now, we multiply the coefficient of x² and the constant term.

4×(-5)=20.

What number when multiplied gives us -20 and when added gives us 8?

The answer is -2 and 10. Thus, we can write 4x²+8x-5 as:

4x²-2x+10x-5.

Take out 2x common from the underlined term and 5 common from the boldened term.

=2x(2x-1)+5(2x-1)

=(2x+5)(2x-1)

=(2x−1)(2x+5)

Thus, 4x²+8x-5=(2x−1)(2x+5)

HOPE THIS HELPS :D