Question

4x2-8x-5=
$4 {x}^ {2} - 8x - 5 = 0$

Answer 1

Hey friend...!!, here's your answer
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${4x }^{2} - 8x - 5 = 0 \\ \\ {4x }^{2} - 10x + 2x - 5 = 0 \\ \\ 2x(2x - 5) + 1(2x - 5) = 0 \\ \\ (2x + 1)(2x - 5) = 0 \\ \\ x = - \frac{1}{2} \: or \: \frac{5}{2}$

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Hope its help

Answer 2

$a = 4 \\ b = - 8 \\ c = - 5 \\ \\ \\ x = \frac{- b + \sqrt{b^2 - 4ac}}{2a} OR \frac{- b - \sqrt{b^2 - 4ac}}{2a} \\ \\ = \frac{-(-8) + \sqrt{(-8)^2 - (4 \times 4 \times-5)}}{2 \times 4} OR \frac{-(-8) - \sqrt{(-8)^2 - (4 \times 4 \times-5)}}{2 \times 4} \\ \\ = \frac{8 + \sqrt{64 - (-80)}}{8} OR \frac{8 - \sqrt{64 - (-80)}}{8} \\ \\ = \frac{8 + \sqrt{64 + 80}}{8} OR \frac{8 - \sqrt{64 + 80}}{8} \\ \\ = \frac{8 + \sqrt{144}}{8} OR \frac{8 - \sqrt{144}}{8} \\ \\ = \frac{8 + 12}{8} OR \frac{8 - 12}{8}$

$\\ \\ = \frac{20}{8} OR \frac{-4}{8} \\ \\ = 2\frac{1}{2} OR - \frac{1}{2}$

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