Question

4x2-8x+9=0 find value of discriminant

Answer 1

Discriminant(d) :-

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Formula :-

$d = \: {b}^{2} - 4 \times a \times c$

Here ,

a = coefficient of x^2 = 4

b = coefficient of x = -8

c = constant term = 9

So

$d \: = \: {( - 8)}^{2} - 4 \times 4 \times 9$

$d \: = \: 64 - 144$

$d \: = \: - 80$

Hope it helps.