4x2+9y2-8x+36y-31=0
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Answer:
The centre is at (1,2)
The vertices are at (12,2),(32,2),(1,2⋅13) and (1,1⋅23)
The foci are at (1−√56,2) and (1+√56,2)
The eccentricity is (√56)
Explanation:
Rearrange the elements to get the standard form of an ellipse
(x−h)2a2+(y−k)2b2=1 where (h,k) is the centre and a and b are the semi-minor and semi-major axes respectively.
So in this example
4x2−8x+9y2−36y+4=0
Using the method of completing squares
4(x2−2x)+9(y2−4y)+4=0
4(x−1)2
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