4x²-(p-2)x+1=0 find the value of p with equation equal roots
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We Know That in Equal root
D=0
Now By applying Sridharacharya Method
D=b^2-4ac
D=(-p+2)^2-4×4×1
D=p^2+4+4p-16
D=p^2+4p-12
NOW WE MADE QUADRATIC POLYNOMIAL
BUT WE KNOW THAT D=0
So
p^2+4p-12=0
p^2+6p-2p-12=0
p(p+6)-2(p+6)=0
(p-2)=0
(p+6)=0
THEREFORE
P=2 or
P=-6
HOPE ITS HELP U....
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