Question

4x2 +x-3=0,find out by quadratic formula .

Answer 1

Answer:

$x = \frac{3}{4} \\ x = - 1 \\ both \: values \: are \: answer$

Step-by-step explanation:

$4 {x}^{2} + x - 3 = 0 \\ d = {b}^{2} - 4ac \\ ( {1}^{2} ) - 4(4)( - 3) = 0 \\ 1 + 48 = 0 \\ 49 \\ x = \frac{ - b + \sqrt{d} }{2a} \\ x = \frac{ - 1 + \sqrt{49} }{8} \\ x = \frac{ - 1 + 7}{8} \\ x = \frac{6}{8} = \frac{3}{4} \\ x = \frac{ - b - \sqrt{d} }{2a} \\ x = \frac{ - 1 - \sqrt{49} }{8} \\ x = \frac{ - 1 - 7}{8} \\ x = \frac{ - 8}{8} \\ x = - 1$

Answer 2

QUESTION:

4x2 +x-3=0,find out by quadratic formula .

FORMULA USED :

$\huge\red {x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} }$

where;

b = coefficient of x

a = coefficient of x square

c = constant term

now come to main question;

Here;

a = 4

b = 1

c = -3

Using the formula;

$\huge\purple {x = \frac{ - 1 \binom{ + }{ - } \sqrt{ {1}^{2} - 4 \times 4 \times - 3} }{2 \times 4} }$

$x = \frac{ - 1 \binom{ + }{ - } \sqrt{1 + 48} }{8}$

$x = \frac{ - 1 \binom{ + }{ - } \sqrt{49} }{8}$

$x = \frac{ - 1 \binom{ + }{ - } \sqrt{7 \times 7} }{8} \\ \\ x = \frac{ - 1 \binom{ + }{ - }7 }{8}$

$\huge\red {x = \frac{ - 1 \binom{ + }{ - }7 }{8}}$

Taking negative;

$x = \frac{ - 1 - 7}{8}$

$x = \frac{ - 8}{8}$

$\huge\orange {x = - 1}$

Taking positive;

$x = \frac{ - 1 + 7}{8} \\ x = \frac{6}{8}$

$\huge\blue {x = \frac{3}{4}}$