Math, asked by fatimamustafa2008, 5 days ago

(4x²y)³÷ 64x²y⁵
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Answers

Answered by misalepatil
0

Answer:

(4x²y)³÷ 64x²y⁵

=4x^6y^3 ÷ 64x²y⁵

=x^4/16y^2

Answered by Dhruv4886
0

Given:

(4x²y)³÷ 64x²y⁵

To Find:

The value of the expression

Solution:

The given expression is an exponent. An exponent is a number raised to some power which can be any real number, it means that how many times that number is multiplied by itself. There are a certain set of rules which needs to be followed when dealing with exponents, they are as follows

x^a*x^b=x^{a+b}\\\frac{x^a}{x^b}=x^{a-b}\\(x^a)^b=x^{ab}

now using these rules to solve the given equation, which goes as

=\frac{(4x^2y)^3}{(64x^2y^5)} \\=\frac{64x^6y^3}{64x^2y^5}\\=\frac{x^4}{y^2}\\=x^4y^{-2}

Hence, the given expression (4x²y)³÷ 64x²y⁵ can be expressed as x^4y^-2.

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