Question

4x³-12x²+14x-3 by 2x-1 by long division​

Answer 1

this attachment may help you .

Answer 2

Step-by-step explanation:

according to reminder theorem we know if f(x) is divided by (x-a) , then reminder is f(a),

if f(x) is divided by (x-a) , we have taken it (x-a) =0 .

So, reminder would be f(a).

Now , p(x) =

$4 {x}^{3} - 12 {x}^{2} + 14x - 3$

If p(x) is divided by 2x-1 ,then (2x-1), it leaves a reminder p(1/2).

$p (\frac{1}{2} ) \\ 4 { (\frac{1}{2}) }^{3} - 12 {( \frac{1}{2} )}^{2} + 14 (\frac{1}{2}) - 3 \\ 4 (\frac{1}{8} ) - 12( \frac{1}{4} ) + 7 - 3 \\ \frac{1}{2} - 3 + 7 - 3 \\ \frac{1}{2} + 1 \\ \frac{3}{2}$

by divison method it is written in the aatechmet....

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