4x3 + 6x² - x by - 1/2x
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1
Given : f(x)=x
4
−4x
3
+6x
2
−4x+1
Differentiate w.r.t x
f
′
(x)=4x
3
−12x
2
+12x−4
=4(x
3
−3x
2
+3x−1)
=4(x−1)
3
i)ifx
′
≥1,f
′
(x)≥0 (Therefore option A is correct)
ii) equate f
′
(x)=0
4(x−1)
3
=0
x=1
iii) f
′′
(x)=12(x−1)
2
f
′′
(x)=0[ifx=1]
f
′′
(x)
f
′′′
(x)=24(x−1)[if(x=1)]
f
′′′′
(x)=+24>0
Therefor this becomes point of minima at x=0⇒ option C is zero.
I give two example please solve you by yourself
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