4x³ +7x² (7x³+ 15x)- (5 x²-8x³+ 7)
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Given,
f(x)=x
3
−7x
2
+15x−9
Let us assume
x−3=0⇒x=3
Now, f(3)=(3)
3
−7(3)
2
+15(3)−9
=27−63+45−9=72−72=0
∴ By remainder theorem,
(x−3) is a factor of f(x)
Now, dividing f(x) by (x−3), we get
x
3
−7x
2
+15−9=(x−3)(x
2
−4x+3)
=(x−3)(x
2
−x−3x+3)
=(x−3){x(x−1)−3(x−1)}
=(x−3)(x−3)(x−1)
=(x−3)
2
(x−1)
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