Question

4x⁴-12x³-x²+27x-18 by long division method​

Answer 1

Answer:

Step-by-step explanation:

4x^4-12x^3-x^2+27x-18

Divident =4x^4-12x^3-x^2+27x-18

-divisor =4x^4-6x^2

remainder= -6x^3-x^2+27x-18

-divisor = -6x^3+9x^2

remainder= -10x^2+27x-18

-divisor = -10x^2+15x

remainder= 12x-18

-divisor = 12x-18

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0

----------Quotient =2x^3-3x^2-5x+6

Remainder = 0

Hope this is helpful.......