Question

4x4-64y4 factorise….

Answer 1

Step-by-step explanation:

4(X⁴- 16Y⁴)

=4{ (X²)²-(4Y²)² }

=4(X² - 4Y²)(X²+4Y²)

=4(X-2Y)(X+2Y)(X²+ 4Y²)

Answer 2

Answer:

$4[(x^{2} + 4y^{2})(x+2y)(x-2y)]$

Step-by-step explanation:

$4x^{4} - 64y^{4}$

We can take 4 as common outside

$4(x^{4} - 16y^{4})$

Now this x4 - 16y4 looks like a2 - b2

here 'a' term is x2 and 'b' term is 4y2

So,

a2 - b2 = (a+b)(a-b)

= $4[(x^{2} + 4y^{2})(x^{2} - 4y^{2} )]$

now again x2 - 4y2 looks like a2 - b2

here 'a' term is x and 'b' term is 2y

so it will be

= $4[(x^{2} + 4y^{2})(x+2y)(x-2y)]$