Math, asked by arunkumarsingh993557, 10 months ago

4xspuare yspuare+1upon4xspuare if (2xspuare+1upon2xy)=1.6​

Answers

Answered by HeroicGRANDmaster
4

Step-by-step explanation:

2xy + 1/2xy = 1.6

वर्ग करने पर

(2xy + 1/2xy)² = (1.6)²

4x²y² + 1/4x²y² + 2(2xy)(1/2xy) = 2.56

4x²y² + 1/4x²y² + 2 = 2.56

4x²y² + 1/4x²y² = 2.56 - 2

= 0.56

Answered by rohin111bhattacharya
0

Answer:

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