Question

(4xsq+6x+2) (4x-3)

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Answer 1

Step-by-step explanation:

STEP

1

Equation at the end of step 1

((4 • (x3)) - (2•3x2)) - 4x = 0

STEP

2

Equation at the end of step

2

(22x3 - (2•3x2)) - 4x = 0

STEP

3

STEP

4

Pulling out like terms

4.1 Pull out like factors :

4x3 - 6x2 - 4x = 2x • (2x2 - 3x - 2)

Trying to factor by splitting the middle term

4.2 Factoring 2x2 - 3x - 2

The first term is, 2x2 its coefficient is 2 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 2 • -2 = -4

Step-2 : Find two factors of -4 whose sum equals the coefficient of the middle term, which is -3 .

-4 + 1 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 1

2x2 - 4x + 1x - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

2x • (x-2)

Add up the last 2 terms, pulling out common factors :

1 • (x-2)

Step-5 : Add up the four terms of step 4 :

(2x+1) • (x-2)

Which is the desired factorization

Equation at the end of step

4

:

2x • (x - 2) • (2x + 1) = 0