Question

4xsquare+4x+1,find the teros andbthe ceoficient​

Answer 1

Step-by-step explanation:

Hey Mate !

Here is your solution :

Given,

Quadratic eq. = 4x² - 4x + 1

Here,

Coefficient of x² ( a ) = 4

Coefficient of x ( b ) = -4

Constant term ( c ) = 1

Now,

=> 4x² - 4x + 1 = 0

=> ( 2x )² - 2 × 2x × 1 + ( 1 )² = 0

Using identity :

=> ( a² - 2ab + b² ) = ( a - b )²

=> ( 2x - 1 )² = 0

=> ( 2x - 1 ) ( 2x - 1 ) = 0 ( continued further )

=> ( 2x - 1 ) = 0 ÷ ( 2x - 1 )

=> ( 2x - 1 ) = 0

=> x = 1/2

★

=> ( 2x - 1 ) = 0 ÷ ( 2x - 1 )

=> ( 2x - 1 ) = 0

=> 2x = 1

=> x = 1/2

Hence, zeroes are ( 1/2 ) and ( 1/2 ).

Now,

=> Sum of zeroes = -b/a

=> ( 1/2 ) + ( 1/2 ) = -( -4 ) ÷ 4

=> ( 1 + 1 )/2 = 4 ÷ 4

=> 2÷2 = 1

=> 1 = 1

And,

=> Product of zeroes = c/a

=> ( 1/2 ) × ( 1/2 ) = 1/4

=> 1/4 = 1/4

★ Verified

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