Question

4xy(y²+6y-16)÷2x(y+8)(y²-4xy²-32xy)
solve it please​

Answer 1

Answer:

factorize y2+6y-16=y2-8y+2y-16=(y-8)(y+2)

now dividing =4xy(y-8)(y+2)/2x(y+8)=2y(y-8)(y+2)/(y+8)

Step-by-step explanation: