Question

4y^2+3y+1/2 by 2y+1 divide

Answer 1

Answer:

please recheck the question how can it be 1/2??

Answer 2

Answer:

2y+1/2

Step-by-step explanation:

2y+1)4y^2+3y+1/2(2y+1/2

4y^2+2y

- -

y+1/2

y+1/2

- -

remainder=0