Question

4y^2-4y+1 factorise these

Answer 1

4y^2_2y_2y+1 =0 => 2y(2y_1) _1(2y_y) =0 => (2y__1) =0, (2y_1)=0 2y=0+1 => y=1/2 , 2y=0+1 => y=1/2

Answer 2

4y^2-2y-2y+1
2y(2y-1)-1(2y-1)
(2y-1)^2