Question

4y^2-4y+1 factorise with suitable identity​

Answer 1

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Here is ur answer mate

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$4y {}^{2} - 4y + 1 = 0 \\ 4y {}^{2} - (2y + 2y) + 1 = 0 \\ 4y {}^{2} - 2y - 2y + 1 = 0 \\ 2y(2y - 1) - 1(2y - 1) = 0 \\ (2y - 1)(2y - 1) = 0 \\ y = \frac{1}{2} \: \: and \: \: \frac{1}{2}$

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Answer 2

Explanation:

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