Math, asked by thakurnishh99, 1 month ago

4y^2-y^3=57, find y?​

Answers

Answered by Anonymous
1

Answer:

y ≈ - 2.87863...

Step-by-step explanation:

4y^2 - y^3 = 57

4y^2 - y^3 - 57 = 57 - 57

-y^3 + 4y^2 - 57 = 0

{ -y^3 + 4y^2 - 57 } / { y + 2.87863... } = - y^2 + 6.87863

{ -y^3 + 4y^2 - 57 } / { y + 2.87863... } = y - 19.80106

y ≈ - 2.87863...

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