Math, asked by lesviahernandez8, 9 months ago

(4y − 3)(2y2 + 3y − 5)

Answers

Answered by ritu16829

0

Answer:

(4y-3)(2y^2+3y-5)

= 8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15

= 8y^3 + 6y^2 - 29y + 15

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