4y^(3) + 6y^(2)+ 2y ÷ 2y
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Answer:
= y² × (4y + 7)
Step-by-step explanation:
⟹ 4y³ + 6y² + 2y ÷ 2y
⟹ 4y³ + 6y² + 2y ÷ 2 × y
⟹ 4y³ + 6y² + y × y
⟹ 4y³ + 6y² + y²
⟹ 4y³ + 7y²
⟹ y² × (4y + 7)
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