4y (3y² + y – 7) and 2(y3 - 4y² + 5)
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Solution
We have,
4y(3y 2 +5y−7)+2(y
3 −4y 2
+5) ⇒12y
3 +20y
2 −28y+2y
3 −8y
2 +10 ⇒14y
3 +12y
2 −28y+10
Hence, this is the answer.
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