4y = 5x – 6 and 3y = 7 – 2x are two simultaneous equations. The value of y in terms of x is: y = 7x – 13. *
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Answer:
Equation I = 2x + 3y = 5
Equation II = 7x - 4y = 3
Multiplying first equation by 4 =
→ 2x + 3y = 5
∴ (2x + 3y = 5) x (4)
= (8x + 12y = 20)......... (equation.III)
Now Multiplying second equation by 3 =
→ 7x - 4y = 3
∴ (7x - 4y = 3) x (3)
= (21x - 12y = 9).......... (equation IV)
Now, Add Equation III with Equation IV.
→ (8x + 12y = 20) + (21x - 12y = 9)
→ (8x + 21x) + (12y - 12y) = (20 + 9)
→ 29x + 0 = 29
→ 29x = 29
→ x = 29/29
→ x = 1
We get : x = 1,
Now Putting x = 1 in Equation I,
→ 2x + 3y = 5
→ 2(1) + 3y = 5
→ 2 + 3y = 5
→ 3y = 5 - 2
→ 3y = 3
→ y = 3/3
→ y = 1
So (x, y) = (1, 1)
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