Question

-4y*square-4y-1.using the fourth identity

Answer 1

$\textbf{\underline{\pink{\underline{\large{Step by step Explanation:-}}}}}$

$\mathrm{-4y^{2}-4y-1=0}$

$\mathrm{\implies{-(-4y^{2}-4y-1)=0}}$

$\mathrm{\implies{4y^{2}+4y+1=0}}$

$\mathrm{\implies{(2y)^{2}+4y+1=0}}$

$\mathrm{\implies{(2y)^{2}+2\times{2y}\times{1}+1^{2}=0}}$

$\mathrm{\implies{(2y+1)^{2}=0}}$

$\mathrm{\implies{2y+1=0}}$

$\mathrm{\implies{2y=-1}}$

$\mathrm{\implies{y=\frac{-1}{2}}}$

$\mathrm{\boxed{\red{y=\frac{-1}{2}}}}$

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