{4y/x}×{2x^5/y^3}×{÷8x^3/y^4}
Answers
Answered by
1
Answer:
there u go
Step-by-step explanation:
Answered by
0
Answer:
Thus, the value of variables is
x
=
2
, and
y
=
5
.
Step-by-step explanation:
Given Data:
The given linear equations are:
4
x
−
y
=
3
⋯
⋯
(
1
)
2
x
+
3
y
=
19
⋯
⋯
(
2
)
Start with the given equations.
4
x
−
y
=
3
2
x
+
3
y
=
19
Multiply the 1st equation by
3
and add with the 2nd. We have:
(
4
x
−
y
)
×
3
+
2
x
+
3
y
=
3
×
3
+
19
12
x
−
3
y
+
2
x
+
3
y
=
9
+
19
14
x
=
28
x
=
28
14
=
2
Put
x
=
2
in equation 1st. We have:
4
x
−
y
=
3
4
×
2
−
y
=
3
y
=
8
−
3
=
5
Thus, the value of variables is
x
=
2
, and
y
=
5
.
Similar questions
Math,
9 days ago
Political Science,
19 days ago
CBSE BOARD XII,
19 days ago
Physics,
9 months ago
English,
9 months ago
Physics,
9 months ago