Question

4y²+4xy+x² factorise the following using suitable identities

Answer 1

4y²+4xy+x²
=(x)²+2×x×2y+(2y)²
Using identity a²+2ab+b²=(a+b)²
=(x+2y)²
=(x+2y)(x+2y)

Answer 2

Answer:

Here is ur answer my frnd

Step-by-step explanation:

4y²+4xy+x²

Identity = a^2 +2ab+b^2

=(2y)²+2×2y×x+(x)²

Using identity a²+2ab+b²=(a+b)²

=(2y+x)²

=(2y+x)(2y+x)