4y²-4y+1, Factorise it using appropriate identities.
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Solution :
Given Quadratic expression is
4y² - 4y + 1
= ( 2y )² - 2 × 2y × 1 + 1²
= ( 2y - 1 )²
[ By algebraic identity,
a² - 2ab + b² = ( a - b )² ]
= ( 2y - 1 )( 2y - 1 )
••••
Given Quadratic expression is
4y² - 4y + 1
= ( 2y )² - 2 × 2y × 1 + 1²
= ( 2y - 1 )²
[ By algebraic identity,
a² - 2ab + b² = ( a - b )² ]
= ( 2y - 1 )( 2y - 1 )
••••
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