Question

4y²-4y+1 factorise this​

Answer 1

Solution :

Given Quadratic expression is

4y² - 4y + 1

= ( 2y )² - 2 × 2y × 1 + 1²

= ( 2y - 1 )²

[ By algebraic identity,

a² - 2ab + b² = ( a - b )² ]

= ( 2y - 1 )( 2y - 1 )

••••

Answer 2

$\mathfrak{\huge{\green{\underline{\underline{Answer :}}}}}$

4y²–4y+1

= (4y²-2y)-(2y+1)

= 2y(2y-1)+(2y-1)

= (2y-1) (2y-1)