Question

4years ago my father's age was 4 times that of my present age. At present the sum of my father's age and that of mine is 53 years .What is my father's present age?​

Answer 1

fathers present age =x years.

sons present age =y years.

four years ago, fathers age =3× sons age.

(x−4)=(y−4)×3

x=3y−8.....(i)

after 4 years, fathers age+ sons age =64

x+4+y+4=64

x+y=56.....(ii)

solve for x

x=3×56−3x−8

4x=160

x=40 years