Math, asked by ChaitanyaGadgil, 11 months ago

4ysquare+8y-5=0 quadratic formula

Answers

Answered by lakshmikrijnvb

1

Answer:

4y²+8y-5=0

4y²+10y-2y-5

2y(2y+5)-1(2y+5)

( 2y-1) (2y+5)

Answered by nikita6010

1

Answer:

HELLO ✌✌

4Y²+8Y-5= 0

4Y²-2Y+10Y-5 = 0

2Y (2Y -1 ) +5 (2Y -1) = 0

(2Y+5) (2Y-1) = 0

(2Y+5)=0 (2Y-1) =0

2Y = -5 2Y = 1

Y= -5/2 Y = 1/2

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