Question

ч) 4yz(z²+6z-16) ÷ 2y(z-8)

Factorise the expressions and divide them as directed​

Answer 1

Answer:

2z(z-2)

Step-by-step explanation:

4yz( z^2+8z-2z-16)

4yz[z(z+8)-2(z+8)]

4yz[(z-2)(z+8)]

--------------------

2y(z+8)

after cancellations

2z(z-2) is the final answer

please mark as brainliest

Answer 2

$4yz( {z}^{2} + 6z - 16) \div 2y(z - 8)$

$4yz( {z}^{2} + 8z - 2z - 16) \div 2y(z - 8)$

$\frac{4yz(z + 8)(z - 2)}{2y(z - 8)}$

$\frac{2z(z + 8)(z - 2)}{(z - 8)}$