Question

4z-3/5 - 2z-1/2 = 1/5-z Solve this?​

Answer 1

Answer:

Hope this would help you

Answer 2

Concept:  Equations with a maximum of one variable of order 1 are referred to as linear equations in one variable equations. It has the formula ax + b = 0, with x serving as the variable.

The following is an example of a linear equation in one variable in its standard form:

Where, ax + b = 0,

Both "a" and "b" are actual numbers.

A and B are not equal to 0 either.

As a result, a linear equation in one variable has the expression

ax + b = 0.

Given: $4z - \frac{3}{5} - 2z - \frac{1}{2} = \frac{1}{5} - z$

To find: the value of 'z'

Solution:

As we are given the equation

$4z - \frac{3}{5} - 2z - \frac{1}{2} = \frac{1}{5} - z\\\\4z - 2z - \frac{3}{5} - \frac{1}{2} = \frac{1}{5} - z\\\\2z + z = \frac{1}{5} + \frac{3}{5} + \frac{1}{2} [ shifting 'z' from RHS to LHS]\\\\3z = \frac{4}{5} + \frac{1}{2}\\\\3z = \frac{8}{10} + \frac{5}{10} \\\\3z = \frac{13}{10} \\\\z = \frac{13}{10 * 3}\\ \\z = \frac{13}{30}$

Hence the value of z = $\frac{13}{30}$

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