Question

4z+3=6+2z solve the following equation & check it out by L. H. S &R. H. S
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Answer 1

4z+3=6+2z.

4z-2z=6-3.

2z=3.

z=3/2.

VERIFICATION:-

4(3/2)+3=6+2(3/2)

(12+6)/2=(12+6)/2.

0=0.

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Answer 2

Answer:

Answered 1 year, 8 months ago

We have 

                  4z + 3 = 6 +2z

Transposing 2z to the LHS and 3 to the RHS, we get:

                   4z - 2z = 6 - 3

or                   2z = 3

DIviding both sides by 2, 

                       

Check:-  Put      in LHS as well as RHS, we have

                LHS :-  4z + 3  

                             

                RHS :-  6 + 2z

                             

Thus,           LHS = RHS