Question

4z+3=6+2z what is the answer and verify​

Answer 1

HI, HERE IS YOUR ANSWER:

4z+3=6+2z

4z-2z=6-3

2z=3

z=3/2

verification:

4*3/2+3=6+2*3/2

6+3=6+3

9=9

therefore, RHS=LHS     (verified)

HOPE IT HELPS YOU!!!

Answer 2

Answer:

The value of the equation is $\frac{3}{2}$ and it satisfies the equation.

Step-by-step explanation:

According to the data given in the question,

We have to find the value of the question, and also verify it.

Given that,

$4z+3=6+2z$

Here we will use the transposition method,

Rearranging the terms, we get

=> $4z+3=2z+6$

Subtract both sides by $3$,

=> $4z+3-3=2z+6-3$

Simplifying it further,

=> $4z=2z+6-3$

Subtract the numbers,

=> $4z=2z+3$

Subtract 2z on both sides,

=> $4z-2z=2z+3-2z$

=> 2z = 3

Divide both sides by 2,

=> $z = \frac{3}{2}$

Hence, the required solution will be $\frac{3}{2} .$

Verification:-

Now, plug the value of z as $\frac{3}{2}$ in the equation,

=> $4(\frac{3}{2}) +3=6+2( \frac{3}{2})$

Simplifying it further,

=> 9 = 9

LHS = RHS