Math, asked by adityarana44536, 20 days ago

4z, - 3z, 8z, - 22 2z

Answers

Answered by juwairiyahimran18

1

$(4z) + (- 3z) + ( 8z) + (- 22) + ( 2z) \\ \\ 4z - 3z + 8z - 22 + 2z \\ \\ 11z - 22 \\ \\ 11(z - 2).$

Answered by Anonymous

1

$(4z)+(−3z)+(8z)+(−22)+(2z) \\ \\ 4z−3z+8z−22+2z \\ \\ 11z−22 \\ \\ 11(z−2).$

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