4z×4z-4z=12
please answers me
z=?
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Answer:
-3/4, 1
Explanation:
According to BODMAS
4zx4z=16z²
Therefore, eq. is
16z²-4z-12=0
dividing whole eq. by 4, we get
4z²-z-3=0
Using Spilliting the middle term, we get
4z²-4z+3z-3=0
4z(z-1)+3(z-1)=0
(4z+3)(z-1)=0
This implies, 4z+3=0 or z-1=0
4z= -3 or z=1
z= -3/4 or z=1 Ans
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