Question

4zn+10hno3gives 4zn(no3)2+nh4no3+3h2o.one mole of hno3 is reduced by how many grams of zinc​

Answer 1

Answer:

determine moles of HNO3

moles = mass / molar mass

= 5.96 g / 63.018 g/mol

= 0.094576 moles HNO3

The balanced equation tells you that

10 moles HNO3 needs 4 moles Zn to fully react

So 1 mole HNO3 will needs 4/10 moles Zn

Thus 0.094576 moles HNO3 needs (4/10 x 0.094576) moles Zn

= 0.03783 moles Zn

1 mole of anything = 6.022x10^23 anythings.

This is called avagadros number

Zn atoms = moles x 6.022x10^23 atoms/mol

= 0.03783 moles x 6.022x10^23 atoms/mol

= 2.28x10^22 atoms of Zn

b.

Work out moles of NH3NO3 required

moles = 87.3 g / 79.044 g/mol

= 1.1044 moles NH3NO3

balanced equaution shows that

1 mole NH3NO3 forms from 4 moles Zn

So 1.1044 moles NH3NO3 forms from (4 x 1.1044) moles Zn

= 4.4178 moles Zn needed

mass = molar mass x moles

= 65.38 g/mol x 4.4178 mol

= 288.84 g

= 289 g (3 sig figs)