Question

5.0 g of copper was heated from 20 celcius to 80 celcius how much energy was used to heat copper? (Specific heat capacity of copper is 0.092 cal/g celcius)

Answer 1

Answer:

The equation to use is:

Q

=

m

c

Δ

t

,

where:

Q

is energy,

m

is mass,

c

is specific heat, and

Δ

t

is change in temperature.

Δ

=

(

T

final

−

T

initial

)

Known

m

=

5 g

c

=

0.38 J

g

⋅

∘

C

Δ

t

=

80

∘

C

−

20

∘

C

=

60

∘

C

Unknown

Q

Solution

Plug the known values into the equation and solve for

Q

.

Q

=

(

5

g

)

×

(

0.38

J

g

⋅

∘

C

)

×

(

60

∘

C

)

=

100 J

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