Question

5.0 t^2 ?
+ 6.0 t+ û
K
4.0 t^3t
: ?
acceleration 2
D
velocity
time
2.5.​

Answer 1

Answer:

Position of the particle x=2t2−t3. Velocity v =dtdx=4t−3t2. Acceleration a=dtdv=4−6t. So, a( at t=2 s) =4−6×2=−8 m/s2. Since, acceleration is depending on the ...please mark me brainliniest