Question

5,000 invested for 5 years at the rate of 4% p.a compounded annually

Answer 1

CI=1083

Step-by-step explanation:

a = p {(1 + \frac{r}{100} )}^{t}a=p(1+

100

r

)

t

where a=amount , p=principle , r=rate , t=time in years

so ,

\begin{gathered}a = 5000 {(1 + \frac{4}{100} )}^{5} \\ = 5000 {(1.04)}^{5} \\ = 5000(1.21665) = 6083\end{gathered}

a=5000(1+

100

4

)

5

=5000(1.04)

5

=5000(1.21665)=6083

Compound Interest =Amount-Principle

=

6083 - 5000 = 10836083−5000=1083

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Answer 2

$\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\red{W}\green{E} \purple{R}}}★$

Step-by-step explanation:

1st year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest, SI=100PTR=1005000×10×6=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =1005300×1×8=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724