(5-1 + 3-1 + 6-1 x 7-1)
0
Answers
Answer:
36
Step-by-step explanation:
(4+2+5x6)
by BODMAS rule
(4+2+30)
(6+30)
=36
Step-by-step explanation:
1 Or 2 roots of given Quadratic equation.
Explanation:
Given
\frac{1}{x+4}-\frac{1}{x-7}=\frac{11}{30}
x+4
1
−
x−7
1
=
30
11
\implies \frac{[x-7-(x+4)]}{(x+4)(x-7)}=\frac{11}{30}⟹
(x+4)(x−7)
[x−7−(x+4)]
=
30
11
\implies\frac{x-7-x-4}{x^{2}-7x+4x-28}=\frac{11}{30}⟹
x
2
−7x+4x−28
x−7−x−4
=
30
11
\implies\frac{-11}{x^{2}-3x-28}=\frac{11}{30}⟹
x
2
−3x−28
−11
=
30
11
Do the cross multiplication, we get
=> 30 = 11(x²-3x-28)/(-11)
=> 30 = -(x²-3x-28)
=> x²-3x-28+30 =0
=> x²-3x+2=0
Splitting the middle term, we get
=> x²-1x-2x+2 =0
=> x(x-1)-2(x-1)=0
=> (x-1)(x-2)=0
=>x-1 = 0 or x-2 = 0
=> x = 1 or x = 2
Therefore,
Roots of the given quadratic equation are 1 , 2
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Solve linear or quadratic inequalities with our free step -by-step algebra calculator. ... x 2+5 x +6=0 ... Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand ...
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