(√5+1)/(√5-1)×(√5+1)/(√5+1)
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(√5+1)(√5-1)×(√5+1)(√5+1)
(√5)²-(1)²×(√5+1)²
5-1×[(√5)²+(1)²+2×√5×1]
4[5+1+2√5]
4[6+2√5]
24+8√5
- (a-b)(a+b) = a²-b²
- (a+b)² = a²+b²+2ab
[all are used in solving this question]
Answered by
1
(√5+1)/(√5-1)×(√5+1)/(√5+1)
(√5+1)/(√5-1)×(√5+1)/(√5+1)
Applying both identity a²-b²= (a+b)(a-b) &
(a+b)² = a²+b²+2ab
= (√5)²-(1)²×[(√5+1)²]
= 5-1[(√5)²+(1)²+2×√5×1]
= 4[5+1+2√5]
= 4[6+2√5]
= 24 + 8√5
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