Question

√5, 1/√5, 1/5√5, 1/25√5 find tn​

Answer 1

Answer:

5^{(3-2n)/2}

Step-by-step explanation:

Given sequence is a GP .

First term a = √5

common ratio r = (1/√5)/√5 = 1/5

Tn = ar^(n-1) = √5 . (1/√5)^(n-1)

=5^(1/2)+(1-n) = 5^{(3-2n)/2}