5 1 8p²4 % p² + 6/25p+ 425
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Answered by
0
Answer:
a³+3a²b+3ab²+b³ = (a+b)³ */
=\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)=(2p+
5
1
)(2p+
5
1
)(2p+
5
1
)
Therefore,
\begin{gathered}Factors < strong > < /strong > \:of \\8p^{3}+\frac{12}{5} p^{2}+\frac{6}{25}p+\frac{1}{125}\\=\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\end{gathered}
Factors<strong></strong>of
8p
3
+
5
12
p
2
+
25
6
p+
125
1
=(2p+
5
1
)(2p+
5
1
)(2p+
5
1
)
Answered by
2
Answer:
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